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VBScript DateDiff Function
 Complete VBScript Reference
The DateDiff function returns the number of intervals between two dates.
Syntax
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DateDiff(interval,date1,date2[,firstdayofweek[,firstweekofyear]])
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| Parameter |
Description |
| interval |
Required. The interval you want to use to calculate the
differences between date1 and date2 Can take the
following values:
- yyyy - Year
- q - Quarter
- m - Month
- y - Day of year
- d - Day
- w - Weekday
- ww - Week of year
- h - Hour
- n - Minute
- s - Second
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| date1,date2 |
Required. Date expressions. Two dates you want to use in
the calculation |
| firstdayofweek |
Optional. Specifies the day of the week. Can take the
following values:
- 0 = vbUseSystemDayOfWeek - Use National Language Support (NLS) API
setting
- 1 = vbSunday - Sunday (default)
- 2 = vbMonday - Monday
- 3 = vbTuesday - Tuesday
- 4 = vbWednesday - Wednesday
- 5 = vbThursday - Thursday
- 6 = vbFriday - Friday
- 7 = vbSaturday - Saturday
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| firstweekofyear |
Optional. Specifies the first week of the year. Can
take the following values:
- 0 = vbUseSystem - Use National Language Support (NLS) API setting
- 1 = vbFirstJan1 - Start with the week in which January 1 occurs
(default)
- 2 = vbFirstFourDays - Start with the week that has at least four days
in the new year
- 3 = vbFirstFullWeek - Start with the first full week of the new year
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Example 1
document.write(Date & "<br />")
document.write(DateDiff("m",Date,"12/31/2002") & "<br />")
document.write(DateDiff("d",Date,"12/31/2002") & "<br />")
document.write(DateDiff("n",Date,"12/31/2002"))
Output:
1/14/2002
11
351
505440
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Example 2
document.write(Date & "<br />")
'Note that in the code below
'is date1>date2
document.write(DateDiff("d","12/31/2002",Date))
Output:
1/14/2002
-351
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Example 3
'How many weeks (start on Monday),
'are left between the current date and 10/10/2002
document.write(Date & "<br />")
document.write(DateDiff("w",Date,"10/10/2002",vbMonday))
Output:
1/14/2002
38
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Complete VBScript Reference
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