MS Access DateDiff() Function
Example
Return the difference between two dates, in years:
SELECT DateDiff("yyyy", #13/01/1998#, #09/05/2017#);
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Definition and Usage
The DateDiff() function returns the difference between two dates.
Syntax
DateDiff(datepart, date1, date2, firstdayofweek,
firstweekofyear)
Parameter Values
Parameter | Description |
---|---|
datepart | Required. The part to return. Can be one of the following values:
|
date1 and date2 | Required. The two dates to calculate the difference between |
firstdayofweek | Optional. Specifies the first day of the week.
Can be one of the following values:
|
firstdayofyear | Optional. Specifies the first week of the year. Can be one of the following values:
|
Technical Details
Works in: | From Access 2000 |
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More Examples
Example
Return the difference between two dates, in months:
SELECT DateDiff("m", #13/01/1998#, #09/05/2017#);
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Example
Return the difference between a specified date and today's date, in days:
SELECT DateDiff("d", #13/01/1998#, Date());
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