SQL Server DATEPART() Function
Example
Return a specified part of a date:
SELECT DATEPART(year, '2017/08/25') AS DatePartInt;
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Definition and Usage
The DATEPART() function returns a specified part of a date.
This function returns the result as an integer value.
Syntax
DATEPART(interval, date)
Parameter Values
Parameter | Description |
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interval | Required. The part of the date argument to return. Can be one of the following values:
|
date | Required. The date to use. Can be one of the following data types: date, datetime, datetimeoffset, datetime2, smalldatetime, or time |
Technical Details
Return type: | int |
---|---|
Works in: | SQL Server (starting with 2008), Azure SQL Database, Azure SQL Data Warehouse, Parallel Data Warehouse |
More Examples
Example
Return a specified part of a date:
SELECT DATEPART(yy, '2017/08/25') AS DatePartInt;
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Return a specified part of a date:
SELECT DATEPART(month, '2017/08/25') AS DatePartInt;
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Example
Return a specified part of a date:
SELECT DATEPART(hour, '2017/08/25 08:36') AS DatePartInt;
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Example
Return a specified part of a date:
SELECT DATEPART(minute, '2017/08/25 08:36') AS DatePartInt;
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