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SQL Server DATEPART() Function

Example

Return a specified part of a date:

SELECT DATEPART(year, '2017/08/25') AS DatePartInt;
Try it Yourself »

Definition and Usage

The DATEPART() function returns a specified part of a date.

This function returns the result as an integer value.

Syntax

DATEPART(interval, date)

Parameter Values

Parameter Description
interval Required. The part of the date argument to return. Can be one of the following values:
  • year, yyyy, yy = Year
  • quarter, qq, q = Quarter
  • month, mm, m = month
  • dayofyear, dy, y = Day of the year
  • day, dd, d = Day of the month
  • week, ww, wk = Week
  • weekday, dw, w = Weekday
  • hour, hh = hour
  • minute, mi, n = Minute
  • second, ss, s = Second
  • millisecond, ms = Millisecond
  • microsecond, mcs = Microsecond
  • nanosecond, ns = Nanosecond
  • tzoffset, tz = Timezone offset
  • iso_week, isowk, isoww = ISO week
date Required. The date to use. Can be one of the following data types: date, datetime, datetimeoffset, datetime2, smalldatetime, or time

Technical Details

Return type: int
Works in: SQL Server (starting with 2008), Azure SQL Database, Azure SQL Data Warehouse, Parallel Data Warehouse

More Examples

Example

Return a specified part of a date:

SELECT DATEPART(yy, '2017/08/25') AS DatePartInt;
Try it Yourself »

Example

Return a specified part of a date:

SELECT DATEPART(month, '2017/08/25') AS DatePartInt;
Try it Yourself »

Example

Return a specified part of a date:

SELECT DATEPART(hour, '2017/08/25 08:36') AS DatePartInt;
Try it Yourself »

Example

Return a specified part of a date:

SELECT DATEPART(minute, '2017/08/25 08:36') AS DatePartInt;
Try it Yourself »