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MS Access DatePart() Function

❮ MS Access Functions


Return the year part of the specified date:

SELECT DatePart("yyyy", #09/05/2017#);
Try it Yourself »

Definition and Usage

The DatePart() function returns a specified part of a date, as an integer.


DatePart(datepart, date, firstdayofweek, firstweekofyear)

Parameter Values

Parameter Description
datepart Required. The date part to return. Can be one of the following values:
  • yyyy = Year
  • q = Quarter
  • m = month
  • y = Day of the year
  • d = Day
  • w = Weekday
  • ww = Week
  • h = hour
  • n = Minute
  • s = Second
date Required. The date value to be evaluated
firstdayofweek Optional. Specifies the first day of the week. Can be one of the following values:
  • 0 = Use the NLS API setting
  • 1 = Sunday (default)
  • 2 = Monday
  • 3 = Tuesday
  • 4 = Wednesday
  • 5 = Thursday
  • 6 = Friday
  • 7 = Saturday
firstdayofyear Optional. Specifies the first week of the year. Can be one of the following values:
  • 0 = Use the NLS API setting
  • 1 = Use the first week that includes Jan 1st (default)
  • 2 = Use the first week in the year that has at least 4 days
  • 3 = Use the first full week of the year

Technical Details

Works in: From Access 2000

More Examples


Return the month part of the specified date:

SELECT DatePart("m", #09/05/2017#);
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Return the weekday of today's date:

SELECT DatePart("w", Date());
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❮ MS Access Functions