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C# User Input


Get User Input

You have already learned that Console.WriteLine() is used to output (print) values. Now we will use Console.ReadLine() to get user input.

In the following example, the user can input his or hers username, which is stored in the variable userName. Then we print the value of userName:

Example

// Type your username and press enter
Console.WriteLine("Enter username:");

// Create a string variable and get user input from the keyboard and store it in the variable
string userName = Console.ReadLine();

// Print the value of the variable (userName), which will display the input value
Console.WriteLine("Username is: " + userName);

Run example »


User Input and Numbers

The Console.ReadLine() method returns a string. Therefore, you cannot get information from another data type, such as int. The following program will cause an error:

Example

Console.WriteLine("Enter your age:");
int age = Console.ReadLine();
Console.WriteLine("Your age is: " + age);

The error message will be something like this:

Cannot implicitly convert type 'string' to 'int'

Like the error message says, you cannot implicitly convert type 'string' to 'int'.

Luckily, for you, you just learned from the previous chapter (Type Casting), that you can convert any type explicitly, by using one of the Convert.To methods:

Example

Console.WriteLine("Enter your age:");
int age = Convert.ToInt32(Console.ReadLine());
Console.WriteLine("Your age is: " + age);

Run example »

Note: If you enter wrong input (e.g. text in a numerical input), you will get an exception/error message (like System.FormatException: 'Input string was not in a correct format.').

You will learn more about Exceptions and how to handle errors in a later chapter.


C# Exercises

Test Yourself With Exercises

Exercise:

Fill in the missing parts to get user input, stored in the variable userName:

Console.WriteLine("Enter username:");
 userName = Console.;
Console.WriteLine("Username is: " + userName);

Start the Exercise